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Differentiate x^{sinx}+sinx^{cosx}

Calculus

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#1 darshan

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Posted 27 September 2013 - 07:33 AM

let me know the answer for this question

#2 richa

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Posted 30 September 2013 - 09:51 AM

Let y = $x^{sinx}+sinx^{cosx}$
u = $x^{sinx}$ v = $sinx^{cosx}$
y = u+v
$\frac{dy}{dx}$= $sinx^{sinx}   \frac{sinx}{x}$  + logcosx+ $sinx^{cosx} (cotxcosx-sinxlogsinx)$





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